Ezekiel's Scribe post for November 4, 2010

Question #22
An aircraft was flying at an altitude of 1950m. It descended for 3 min at 2.5 m/s and then descended for 2.5 min at 2.8 m/s. What was the plane's altitude after the descent?

The plane is descending for 3 minutes at 2.5 m/s

1 minute has 60 seconds so 60 x 3 = 180

Then you multiply 180 by 2.5

180 x 2.5 = 450

now u can subtract 2950 by 450

2950 - 450 = 2500 m

now the plane is descending down for 2.5 minutes at 2.8 m/s

multiply the 60 seconds by the minutes going down
60 x 2.5 = 150

now times the seconds by the m/s which is 2.8

150 x 2.8 = 420

now subtract 420 by 2500

2500 - 420 = 2080 m
The altitude of the plane after the descend is 2080 m