Raquel's scribepost for October 12th

Today, in math class we had to solve some questions. (By the way, I'm going to be taking pictures instead of drawing it on paint and typing how to solve it cause, I think it's easier to take pictures so yeah. )
Such as:





Yeah, those are the questions in the beginning of the class. ( If you can't see the picture, GET GLASSES. just kidding. just click it to make it really large. (: )

Then, Mr.Backe taught us how to find this triangular roof. This is how you solve it:


We did a similar question which looks like:

That's pretty much it on what we did for today's math class. :)

HOMEWORK:
You have to solve these shapes:

( Remember to click the pictures if you can't see it!!! )
Mr.Backe is also collecting the foldables and the journals tomorrow. So make sure your done it all.!!!!!!
MAAAAATH TEST TOMORROOOOOOW!!
I pick .................. KATHLEEN MAULA FOR NEXT SRIBEPOST. Love you Kathleen. :) Hope you have fun . Bwuahahahhaha.

Ezekiel's Scribe Post for October 7th, 2010

Today in math Mr. Backe showed us how to do our homework that we had to do.

The Answer:
Whole Shape
S.A. = 2(L) (W) + 2(L) (H) + 2(W) (H)
S.A. = 2(12) (5) + 2(12) (10) + 2(10) (5)
S.A. = 120+240+100
S.A. = 460 u ²
Hole Taken out
S.A. = 2(L) (W) + 2(L) (H) + 2(W) (H)
S.A .= 2(4) (5) + 2(4) (6) + 2(5) (6)
S.A. = 40+48+60
S.A. = 148 u ²
Faces Taken Out
S.A. = 2(LH)
S.A. = 2(4x6)
S.A. = 48
Total Surface Area
S.A. = 460+148-48
T.S.A. = 560 u ²
Mr. Backe asked us if we understood how to do surface area. Some of us didn't understand so he gave us another question. He told us we could do it on our own if we wanted. I did it on my own

The Answer:
Whole Shape
S.A. = 2(L) (W) + 2(L) (H) + 2(W) (H)
S.A. = 2(7) (8) + 2(7) (9) + 2(8) (9)
S.A. = 112+126+144
S.A. = 382 u ²
inside the hole
S.A. = 2(L) (W) + 2(L) (H) + 2(W) (H)
S.A. = 2(3) (8) + 2(3) (4) + 2(8) (4)
S.A. = 48+24+64
S.A. = 136 u ²
Faces Taken off
S.A. = 2(LH)
S.A. = 2(3 x 4)
S.A. = 24 u ²
Total Surface Area
S.A. = 382+136-24
T.S.A = 494 u ²

When everybody understood how to do the cube Mr.Backe showed asked us if we remembered how to find the circumference of a circle.
Circumference formula's: 2╥r or ╥d

Then he told us the formula for a cylinder
2╥rh+2╥r²
Then he gave us a cylinder that we were gonna do together.


Mr.Backe asked us how to find the radius from the diameter
r = d/2
r = 6/2
r = 3 cm
then he asked us to make a net of the cylinder

now we can solve the cylinders surface area
S.A. = 2╥rh+2╥r²
S.A. = 2╥(3) (12) + 2╥(3²)
S.A. = 229.19+56.55
S.A. = 282.74 cm²

I didn't put the first cylinder that we did together so.
r=d/2
r=10/2
r=5
S.A. = 2╥rh+2╥r²
S.A. = 2╥(5) (20)+2╥(5²)
S.A. = 628.32+157.08
S.A. = 785.4 cm ²
Remember for homework was in apply questions 13, 14, and 15 and Tutpup everyday


Also I pick Karra for the next scribe post. Have fun >:D